What is the molarity of NaCl when 3.46 g of NaCl is dissolved in water to form 50.0 mL of solution?

1 Answer
Jan 15, 2018

Answer:

#[NaCl(aq)]=*mol*L^-1~=1.20*mol*L^-1#..

Explanation:

For #"molarity"# we take the quotient...#"moles of solute"/"volume of solution"#...and we get an answer with units of #mol*L^-1#..

And so....#((3.46*g)/(58.44*g*mol^-1))/(50.0*mLxx10^-3*L*mL^-1)=??*mol*L^-1#...

What are the values of #[Na^+]# and #[Cl^-]#?