What is the mole fraction of methanol in a solution that contains 6.0 mol of methanol and 3.0 mol of water? The formula for methanol is CH_3OH.

Feb 11, 2017

$\text{The mole fraction of methanol is}$ $\frac{2}{3}$.
${\chi}_{\text{MeOH}}$ $=$ $\text{Moles of MeOH"/"Moles of methanol + moles of water}$
$\frac{6.0 \cdot m o l}{\left(6.0 + 3.0\right) \cdot m o l} = \frac{2}{3}$ as required.............
What is the $\text{mole fraction of water?}$