What is the mole fraction of #NaOH# in an aqueous solution that contains 15.0% #NaOH#?

1 Answer
Jul 7, 2017

Answer:

See Below :)

Explanation:

15% NaOH by mass is 15g of NaOH in (100-15)g of solution.

No. Of moles of NaOH in solution = 0.65

No of moles of Water in solution = 4.72

Mole Fraction = #("(Moles of Solvent)"/"(Moles Of Solute)+(Moles of Solvent)")#
OR
#("(Moles of Solvent)"/"Total Number Of Moles")#

= 0.65 / 5.37
= 0.121

PS - Calculated this as per 'What is the mole fraction of NaOH in an aqueous solution that contains 15.0% NaOH by mass?'