# What is the mole ratio of Cl_2 to Br_2 in the reaction Cl_2+2NaBr->2NaCl+Br_2?

The mole ratio of ${\text{Cl}}_{2}$ and ${\text{Br}}_{2}$ is $\textcolor{b l u e}{\text{1 mol Cl"_2}}$$:$$\textcolor{b l u e}{\text{1 mol Br"_2}}$.
There is no coefficient in front of the $\text{Cl"_2}$ or the $\text{Br"_2}$, which is understood to be 1 mole.