What is the moment of inertia of a pendulum with a mass of $2 k g$ $2 kg$ that is $4 m$ $4 m$ from the pivot?

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Answer 1 · 2017-02-21T07:01:17

The moment of inertia is $= 32 k g m^{2}$ $=32 kgm^2$

The moment of inertia is

$I = m r^{2}$ $I=mr^2$

$I = (2 \cdot 4^{2}) k g m^{2}$ $I=(2*4^2)kgm^2$

$= 32 k g m^{2}$ $=32 kg m^2$

What is the moment of inertia of a pendulum with a mass of 2 kg2kg2 kg that is 4 m4m4 m from the pivot?