# What is the moment of inertia of a pendulum with a mass of 2 kg that is 6 m from the pivot?

Feb 8, 2016

$72 {\text{kgm}}^{2}$

#### Explanation:

Assumptions:

1. You are referring to the moment of inertia about the axis passing through the pivot.

2. The pendulum is small enough to be treated as a point mass.

$I = M {R}^{2}$

$= {\left(2 \text{kg") (6 "m}\right)}^{2}$

$= 72 {\text{kgm}}^{2}$