What is the moment of inertia of a pendulum with a mass of #2 kg# that is #8 m# from the pivot?

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Answer 1 · 2017-03-06T17:48:02

The moment of inertia is #=128kgm^2#

The moment of inertia of the pendulum is

#I=mr^2#

Where

the mass is #m=2kg#

The distance from the pivot is #r=8m#

The moment of inertia is

#I=mr^2=2*8^2=128kgm^2#