# What is the moment of inertia of a pendulum with a mass of 2 kg that is 8 m from the pivot?

Mar 6, 2017

The moment of inertia is $= 128 k g {m}^{2}$

#### Explanation:

The moment of inertia of the pendulum is

$I = m {r}^{2}$

Where

the mass is $m = 2 k g$

The distance from the pivot is $r = 8 m$

The moment of inertia is

$I = m {r}^{2} = 2 \cdot {8}^{2} = 128 k g {m}^{2}$