# What is the moment of inertia of a pendulum with a mass of 3 kg that is 10 m from the pivot?

Apr 21, 2018

$300 \setminus \text{kg m"^2}$

#### Explanation:

Moment of inertia of a simple pendulum is given by:

$I = m {r}^{2}$

• $m$ is the mass of the object in kilograms

• $r$ is the distance of the pendulum from the pivot

And so, we get:

I=3 \ "kg"*(10 \ "m")^2

$= 3 \setminus {\text{kg"*100 \ "m}}^{2}$

$= 300 \setminus {\text{kg m}}^{2}$