Question

What is the moment of inertia of a pendulum with a mass of `3 kg` that is `12 m` from the pivot?

Answer 1

`432 Kg.m^2`

Explanation:

Consider the bob of the pendulum to be a point mass as radius is not given.

So moment of inertia of a mass `m` at a distance of `l` from a pivoted point is `ml^2`

Given, `m=3Kg` and `l=12m`

So,its moment of inertia will be `3×(12)^2 Kg.m^2` or `432 Kg.m^2`