# What is the moment of inertia of a pendulum with a mass of 4 kg that is 2 m from the pivot?

Feb 28, 2017

The moment of inertia is $= 16 k g {m}^{2}$

#### Explanation:

The moment of inertia is

$I = m {r}^{2}$

$m = 4 k g$

$r = 2 m$

$I = m {r}^{2} = 4 \cdot {2}^{2} = 16 k g {m}^{2}$