# What is the moment of inertia of a pendulum with a mass of 4 kg that is 4 m from the pivot?

$64 \text{ } k g . {m}^{2}$
moment of Inertia, $I = m {r}^{2} = 4 \times {4}^{2} \text{ "kg.m^2=64 " } k g . {m}^{2}$