What is the moment of inertia of a pendulum with a mass of 5 kg that is 13 m from the pivot?

Apr 6, 2017

The moment of inertia $= 845 k g {m}^{2}$

Explanation:

The moment of inertia is

$I = m {r}^{2}$

The mass is $= 5 k g$

The radius is $= 13 m$

The moment of inertia is

$I = 5 \cdot {13}^{2} = 845 k g {m}^{2}$