Question

What is the moment of inertia of a pendulum with a mass of `5 kg` that is `13 m` from the pivot?

Answer 1

The moment of inertia `=845kgm^2`

Explanation:

The moment of inertia is

`I=mr^2`

The mass is `=5kg`

The radius is `=13m`

The moment of inertia is

`I=5*13^2=845kgm^2`