What is the moment of inertia of a pendulum with a mass of 5 kg that is 4 m from the pivot?

Mar 1, 2017

Moment of inertia $= 80 k g - {m}^{2}$

Explanation:

Moment of inertia $= m {r}^{2}$

Moment of inertia $= 5 \times {4}^{2}$

Moment of inertia $= 5 \times 16$

Moment of inertia $= 80 k g - {m}^{2}$