# What is the moment of inertia of a pendulum with a mass of 6 kg that is 4 m from the pivot?

Apr 5, 2018

$96 \setminus {\text{kg m}}^{2}$

#### Explanation:

Moment of inertia of a simple pendulum is given by:

$I = m {r}^{2}$

• $m$ is the mass of the bob in kilograms

• $r$ is the distance of the pendulum from the pivot in meters

And so,

I=6 \ "kg"*(4 \ "m")^2

$= 6 \setminus {\text{kg"*16 \ "m}}^{2}$

$= 96 \setminus {\text{kg m}}^{2}$