What is the moment of inertia of a pendulum with a mass of #6 kg# that is #4 m# from the pivot?

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Answer 1 · 2018-04-05T12:39:33

#96 \ "kg m"^2#

Moment of inertia of a simple pendulum is given by:

#I=mr^2#

#m# is the mass of the bob in kilograms

#r# is the distance of the pendulum from the pivot in meters

And so,

#I=6 \ "kg"*(4 \ "m")^2#

#=6 \ "kg"*16 \ "m"^2#

#=96 \ "kg m"^2#