# What is the moment of inertia of a pendulum with a mass of 7 kg that is 3 m from the pivot?

Mar 5, 2017

$I = 63 k g {m}^{2}$

#### Explanation:

Moment of inertia is the product of mass and distance squared,

$I = m {r}^{2}$

Here the mass is $7$ and the distance is $3$, so

$I = 7 \times {3}^{2} = 7 \times 9 = 63 k g {m}^{2}$