# What is the moment of inertia of a pendulum with a mass of 7 kg that is 4 m from the pivot?

May 16, 2016

$m o m e n t = 280 N m$
first of all convert $7 k g$ into Newtons by multiplying by $10$ as it is the gravitational force.
so $7 \cdot 10 = 70 N$
$m o m e n t = N \cdot d$
$m o m e n t = 70 \cdot 4$
$m o m e n t = 280 N m$