# What is the moment of inertia of a pendulum with a mass of 7 kg that is 9 m from the pivot?

Mar 30, 2018

$567 \setminus {\text{kg m}}^{2}$

#### Explanation:

The moment of inertia of pendulum is given by:

$I = m {r}^{2}$

• $m$ is the mass in kilograms

• $r$ is the distance from the pivot in meters

So here, we get:

I=7 \ "kg"*(9 \ "m")^2

$= 7 \setminus {\text{kg"*81 \ "m}}^{2}$

$= 567 \setminus {\text{kg m}}^{2}$