# What is the moment of inertia of a pendulum with a mass of 8 kg that is 7 m from the pivot?

Apr 15, 2017

The moment of inertia is $= 392 k g {m}^{2}$

#### Explanation:

The moment of inertia is

$I = m \cdot {r}^{2}$

mass, $m = 8 k g$

radius, $r = 7 m$

$I = 8 \cdot {7}^{2} = 392 k g {m}^{2}$