What is the moment of inertia of a pendulum with a mass of #9 kg# that is #12 m# from the pivot?

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Answer 1 · 2018-03-23T04:37:08

#1296 \ "kg m"^2#

Moment of inertia of a simple pendulum is given by:

#I=mr^2#

#m# is the mass of the pendulum bob

#r# is the distance of the pendulum from the pivot

So, we plug in our given values, and we get,

#I=9 \ "kg"*(12 \ "m")^2#

#=9 \ "kg"*144 \ "m"^2#

#=1296 \ "kg m"^2#