What is the moment of inertia of a rod with a mass of #3 kg# and length of #4 m# that is spinning around its center?

1 Answer

Answer:

Moment of inertia of given rod is #4kgm^2#.

Explanation:

As the rod is spinning on its own centre , we are considering the moment of inertia of rod with axis perpendicular to rod at midpoint i.e., #I = (mr^2)//12#
This can be done by calculating the moment of inertia of a system #I= Sigmam_i(r_i)^2#.
Now calculating the moment of inertia of rod with given values we get
#I = [3xx(4)^2]//12=4kgm^2#.