What is the moment of inertia of a rod with a mass of 4 kg and length of 15 m that is spinning around its center?

$I = \frac{1}{12} \cdot 4 k g \cdot {\left(15 m\right)}^{2} = \frac{225}{3} k g \cdot {m}^{2}$
Moment of Inertia, $I = \frac{1}{12} m {l}^{2}$
m=4kg; l=15m
$I = \frac{1}{12} \cdot 4 k g \cdot {\left(15 m\right)}^{2} = \frac{225}{3} k g \cdot {m}^{2}$