# What is the moment of inertia of a rod with a mass of 7 kg and length of 13 m that is spinning around its center?

Dec 13, 2016

The moment of inertia is $= 98.6 k g {m}^{2}$

#### Explanation:

The moment of inertia of a rod is $I = \frac{1}{12} m {l}^{2}$

$m$=mass of the rod=7kg

$l =$length of the rod=13m

$I = \frac{1}{12} \cdot 7 \cdot {13}^{2} = 98.6 k g {m}^{2}$