# What is the moment of inertia of a rod with a mass of 7 kg and length of 2 m that is spinning around its center?

Mar 9, 2018

$I = 14 \setminus {\text{kg m}}^{2}$

#### Explanation:

The moment of inertia of a rod is given by:

$I = \frac{1}{2} M {L}^{2}$

Source:

http://hyperphysics.phy-astr.gsu.edu/hbase/mi2.html

We got: $M = 7 \setminus \text{kg", L=2 \ "m}$

$\therefore I = \frac{1}{2} \cdot 7 \setminus {\text{kg"*4 \ "m}}^{2}$

$= 14 \setminus {\text{kg m}}^{2}$