What is the moment of inertia of a rod with a mass of #7 kg# and length of #2 m# that is spinning around its center?

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Nam D. Share
Mar 9, 2018

Answer:

#I=14 \ "kg m"^2#

Explanation:

The moment of inertia of a rod is given by:

#I=1/2ML^2#

Source:

http://hyperphysics.phy-astr.gsu.edu/hbase/mi2.html

We got: #M=7 \ "kg", L=2 \ "m"#

#:.I=1/2*7 \ "kg"*4 \ "m"^2#

#=14 \ "kg m"^2#

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