What is the moment of inertia of a rod with a mass of #7 kg# and length of #2 m# that is spinning around its center?

Question

1511 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-09T04:13:25

#I=14 \ "kg m"^2#

The moment of inertia of a rod is given by:

#I=1/2ML^2#

Source:

We got: #M=7 \ "kg", L=2 \ "m"#

#:.I=1/2*7 \ "kg"*4 \ "m"^2#

#=14 \ "kg m"^2#