# What is the moment of inertia of a rod with a mass of 7 kg and length of 6 m that is spinning around its center?

Mar 4, 2016

$21 \quad {\text{kgm}}^{2}$

#### Explanation:

The moment of inertia of a homogenous rod with mass $M$ and length $L$ about its center, $I$, is given by

$I = \frac{1}{12} M {L}^{2}$

$= \frac{1}{12} {\left(7 \quad \text{kg") (6 quad "m}\right)}^{2}$

$= 21 \quad {\text{kgm}}^{2}$