Question

What is the moment of inertia of a rod with a mass of `7 kg` and length of `6 m` that is spinning around its center?

Answer 1

`21 quad "kgm"^2`

Explanation:

The moment of inertia of a homogenous rod with mass `M` and length `L` about its center, `I`, is given by

`I = 1/12 ML^2`

`= 1/12 (7 quad "kg") (6 quad "m")^2`

`= 21 quad "kgm"^2`