# What is the name for the compound with the formula Sn(CrO_4)_2?

Jul 16, 2017

Stannic chromate or tin(IV) chromate

#### Explanation:

We're asked to find the name of the compound ${\text{Sn(CrO"_4")}}_{2}$.

This is considered an ionic compound, with the constituent ions being

• a tin cation

• the chromate anion, ${\text{CrO}}_{4}^{2 -}$

This being a compound, the sum of the ionic charges must be $0$.

We know the charge of the chromate ion is $2 -$, so we need to find the charge of the $\text{Sn}$ cation, by asking, "What must the charge (oxidation state) of tin be so that the net charge is zero?"

There is one cation per two anions in this compound, so we have

overbrace((1)(x))^"tin" + overbrace((2)(-2))^("CrO"_4^(2-)) = 0

x = color(red)(4

The oxidation state of tin here is thus $\left(I V\right)$, so the name is

Tin(IV) chromate

or

Stannic chromate