What is the name for the compound with the formula #Sn(CrO_4)_2?#

1 Answer
Jul 16, 2017

Answer:

Stannic chromate or tin(IV) chromate

Explanation:

We're asked to find the name of the compound #"Sn(CrO"_4")"_2#.

This is considered an ionic compound, with the constituent ions being

  • a tin cation

  • the chromate anion, #"CrO"_4^(2-)#

This being a compound, the sum of the ionic charges must be #0#.

We know the charge of the chromate ion is #2-#, so we need to find the charge of the #"Sn"# cation, by asking, "What must the charge (oxidation state) of tin be so that the net charge is zero?"

There is one cation per two anions in this compound, so we have

#overbrace((1)(x))^"tin" + overbrace((2)(-2))^("CrO"_4^(2-)) = 0#

#x = color(red)(4#

The oxidation state of tin here is thus #(IV)#, so the name is

Tin(IV) chromate

or

Stannic chromate