# What is the neutralization reaction with the combination H3BO3 and BaOH?

$2 {H}_{3} B {O}_{3}$ + $3 B a {\left(O H\right)}_{2}$ $\to$ 6 ${H}_{2} O$ + $B {a}_{3} \left(B {O}_{3}\right) 2$
The OH- group from the base combines with the H+ from the acid to produce water. The cation from the base (in this case $B {a}^{2} +$ ) combines with the anion (borate) from the acid.