Question

What is the nth term of 1,2,4,8,16,32?

Answer 1

It's apparent that the first term is `1` and the ratio is `2`

Explanation:

In 'the language':
`u_0=1,r=2`

Then:
`u_n=u_0xxr^n`

But:
This is not the `n`th term, as the first one is called `u_0`
So you need `u_(n-1)=u_0xxr^(n-1)`

Example:
The tenth term would be nine steps away from the first (called `0`), which would translate to `u_9=1xx2^9=512`