# What is the nth term of 1,2,4,8,16,32?

##### 1 Answer
Mar 21, 2016

It's apparent that the first term is $1$ and the ratio is $2$

#### Explanation:

In 'the language':
${u}_{0} = 1 , r = 2$

Then:
${u}_{n} = {u}_{0} \times {r}^{n}$

But:
This is not the $n$th term, as the first one is called ${u}_{0}$
So you need ${u}_{n - 1} = {u}_{0} \times {r}^{n - 1}$

Example:
The tenth term would be nine steps away from the first (called $0$), which would translate to ${u}_{9} = 1 \times {2}^{9} = 512$