What is the number of atoms in 23.227 g of Cr?

1 Answer
Sep 14, 2016

Answer:

#6.022xx10^23*mol^-1xx(23.227*g)/(51.996*g*mol^-1)# #=# #??" atoms"#

Explanation:

It is a fact that #"Avogadro's number"#, #6.022xx10^23# #"chromium atoms"# have a mass of #51.996*g#. From where did I get this mass?

So all we have to do is divide the given mass by the molar mass, and mulitply this number by #"Avogadro's number"#, #6.022xx10^23# to give the number of chromium atoms.

We get approx. #3xx10^23" chromium atoms."#