# What is the number of atoms of hydrogen in 1.00 pg of humulone?

Sep 7, 2017

Well, $1 \cdot p g \equiv 1 \times {10}^{-} 12 \cdot g = 1 \times {10}^{-} 15 \cdot k g \ldots . .$. I do not know what humulone is.
$\text{Moles "xx" Molar quantity}$. And so if we had $1 \times {10}^{12} \cdot g$ of hydrogen, we could work out the number of hydrogen atoms.
$\frac{1 \times {10}^{-} 12 \cdot g}{1.00794 \cdot g \cdot m o {l}^{-} 1} \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1 = 6.0 \times {10}^{11}$ individual hydrogen atoms....