# What is the number of C, H, and O atoms in 1.5 g of glucose, C_6H_12O_6?

Dec 19, 2015

Carbon Atoms = $3.01 \cdot {10}^{22}$
Hydrogen Atoms = $6.02 \cdot {10}^{22}$
Oxygen Atoms = $3.01 \cdot {10}^{22}$

#### Explanation:

You first need to convert the $1.5$ Grams of Glucose to Moles of Glucose:

$\text{1.5 grams of glucose"/"180.15588 grams/moles glucose}$ = $.008326$ Moles of Glucose

Next you'll want to find the formula units of glucose by using avagadro's number:

$.008326 {\text{Moles of Glucose"*6.022*10^23 "Formula Units*Moles}}^{-} 1$=

$5.01 \cdot {10}^{21}$ Formula Units of Glucose

The final step is to multiply the Formula units of glucose by the amount of each element in the molecule

For example:

$6 \text{carbon's} \cdot 5.01 \cdot {10}^{21} = 3.01 \cdot {10}^{22}$

and repeat for oxygen and hydrogen