What is the number of C, H, and O atoms in 1.5 g of glucose, #C_6H_12O_6#?

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Answer 1 · 2015-12-19T18:19:21

Carbon Atoms = #3.01*10^22#
Hydrogen Atoms = #6.02*10^22#
Oxygen Atoms = #3.01*10^22#

You first need to convert the #1.5# Grams of Glucose to Moles of Glucose:

#"1.5 grams of glucose"/"180.15588 grams/moles glucose"# = #.008326# Moles of Glucose

Next you'll want to find the formula units of glucose by using avagadro's number:

#.008326 "Moles of Glucose"*6.022*10^23 "Formula Units*Moles"^-1#=

#5.01*10^21# Formula Units of Glucose

The final step is to multiply the Formula units of glucose by the amount of each element in the molecule

For example:

#6 "carbon's" * 5.01*10^21 = 3.01*10^22#

and repeat for oxygen and hydrogen