# What is the number of moles of calcium cyanide in 320 g calcium cyanide?

May 10, 2017

As always, "Number of moles"-="Mass"/"Molar mass"=???mol
Number of moles of $C a {\left(C \equiv N\right)}_{2} = \frac{320 \cdot g}{92.11 \cdot g \cdot m o {l}^{-} 1} \cong 3 \cdot m o l$.
The equation is dimensionally consistent in that $\frac{1}{m o {l}^{-} 1} = \frac{1}{\frac{1}{m o l}} = m o l$, as required for an answer in $\text{moles.}$