What is the number of moles of #O_2# that will react with 10.0g of #H_2# to form water in the equation #2H_2 + O_2 -> 2H_2O#?

1 Answer
May 29, 2017

Answer:

2.48 moles of #O_2# will react with 10.0g of #H_2# to form water.

Explanation:

For this problem, we should implement the process of stoichiometry. First, convert the grams of #H_2# into moles:

#10.0g H_2xx(1molH_2)/(2.01588 g H_2)#

Then multiply by your mole to mole ratio:

#10.0 g H_2xx(1 mol H_2)/(2.01588 g H_2)xx(1 mol O_2)/(2 mol H_2)#

Cancel out common terms and perform the math to get your answer:

#10.0 cancel(g H_2)xx(1 cancel(mol H_2))/(2.01588 cancel(g H_2))xx(1 mol O_2)/(2 cancel(mol H_2))= 2.48 mol O_2#

The answer has three sig figs because of the given 10.0g.