What is the number of representative particles in #4.80 * 10^-3# mol #NaI#?

1 Answer
anor277
Apr 6, 2016

#9.6xx10^-3# total moles of ions.

Explanation:

A sodium iodide unit is conceived to derive from one #Na^+# and one #I^-#. Because matter is electrically neutral these combine in a 1:1 fashion.

You specified #4.80xx10^-3# #mol# of #NaI#. In this molar quantity there are #4.80xx10^-3# #mol# of #Na^+# ions, and #4.80xx10^-3# #mol# of #I^-#; i.e. #9.6xx10^-3# of individual ions.

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