What is the % of #C# in #C_6H_12O_6#?

1 Answer
Sep 1, 2017

Answer:

#40%#.............

Explanation:

#"% carbon"="Mass of carbon"/"Mass of glucose"xx100%#

#(6*xx12.011*g*mol^-1)/(180.16*g*mol^-1)xx100%#

#=40%#