What is the oxidizing agent in the following net ionic equation of a reaction? 4H+ (aq) + SO4^2-(aq) + 2NaI (s) --> 2 Na+ (aq) + I2 (s) + SO2 (g) + 2 H2O (l)

1 Answer
Apr 3, 2018

See below

Explanation:

Oxidizing agent is the species that is reduced, being reduced means to gain electrons and have a lowered oxidation number

Let's see:
#I^-# in the reactants to #I^(+0)#, increased oxidation state therefore it was oxidized

#Na^+# to #Na^+# no change

#S^(+6)# in the reactants to #S^(+4)#, decreased oxidation state therefore it was reduced, so the sulfate ion acted as the oxidizing species by being reduced