Question

What is the percent by mass of `NaHCO_3` in a solution containing 20 g `NaHCO_3`, dissolved in 600 mL `H_2O`?

Answer 1

`"Approx. 3%"`

Explanation:

We simply work out the quotient:

`"Mass of sodium bicarbonate"/"Mass of sodium bicarbonate solution"xx100%=`

`(20*g)/(20*g+600*g)xx100%=3.2%(m/m)`