What is the percent composition of Magnesium(Mg) in the compound Magnesium Chloride (MgCl) ?

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What is the percent composition of Magnesium(Mg) in the compound Magnesium Chloride (MgCl) ?

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Answer 1 · 2018-02-27T00:07:45

The percent composition of $Mg$ $"Mg"$ in ${MgCl}_{2}$ $"MgCl"_2"$ is $25.529%$ $"25.529%"$ .

Explanation:

The correct formula for magnesium chloride is ${MgCl}_{2}$ $"MgCl"_2"$ .

To determine the percent composition of $Mg$ $"Mg"$ , divide the molar mass of $Mg$ $"Mg"$ by the molar mass of ${MgCl}_{2}$ $"MgCl"_2"$ and multiply by $100 %$ $100%$ .

$M_{Mg} :$ $M_"Mg":$ $24.305 g/mol$ $"24.305 g/mol"$ (atomic weight of periodic table in g/mol)

$M_{MgCl2} :$ $M_"MgCl2":$ $(24.305 g/mol Mg) + (2 \times 35.45 g/mol Cl) = 95.305 g/mol$ $(24.305"g/mol Mg")+(2xx35.45"g/mol Cl")="95.305 g/mol"$

Percent composition of Mg

$"% Mg"=(24.305color(red)cancel(color(black)("g/mol")))/(95.205color(red)cancel(color(black)("g/mol")))xx100%="25.529% Mg"$

The percent composition of $"Mg"$ in $"MgCl"_2"$ is $"25.529%"$ .

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What is the percent composition of Magnesium(Mg) in the compound Magnesium Chloride (MgCl) ?

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