# What is the percent composition of nitrogen for Sr(NO_3)_2?

Nov 17, 2016

13.237 %

#### Explanation:

The molecular weight of Sr(NO3)2 is 211.62 gm
Atomic weight of Nitrogen is 14.0067 gm
Since there is two atoms of Nitrogen in Sr(NO3)2
Therefore total Nitrogen is $14.0067 \cdot 2$ = 28.0134
Since 28.0134 gm Nitrogen is in 211.62 gm Sr(NO3)2
Hence what is for per 100 gm [ percent] of Sr(NO3)2

So

$28.0134 \cdot \frac{100}{211.62}$ = 13.237