What is the percent composition of nitrogen for #Sr(NO_3)_2#?

1 Answer
Nov 17, 2016

Answer:

13.237 %

Explanation:

The molecular weight of Sr(NO3)2 is 211.62 gm
Atomic weight of Nitrogen is 14.0067 gm
Since there is two atoms of Nitrogen in Sr(NO3)2
Therefore total Nitrogen is #14.0067*2# = 28.0134
Since 28.0134 gm Nitrogen is in 211.62 gm Sr(NO3)2
Hence what is for per 100 gm [ percent] of Sr(NO3)2

So

#28.0134*100/211.62# = 13.237

Hence Answer is 13.237 %