# What is the percentage composition of CF_4?

Feb 8, 2016

13.6% C and 86.4%F

#### Explanation:

The percent composition of an element in a compound is given by:

(("Atomic mass")xx("subscript"))/("molar mass of the compound")xx100%

Therefore, for the compound $C {F}_{4}$:

%C=(12.0xx1)/(88.0)xx100%=13.6%

%C=(19.0xx4)/(88.0)xx100%=86.4%