# What is the percentage composition of NH_4I?

Jan 1, 2018

Well, the molar mass of ammonium iodide is $144.94 \cdot g \cdot m o {l}^{-} 1$...

#### Explanation:

And so %I-=(126.9*g*mol^-1)/(144.94*g*mol^-1)xx100%=87.6%

And %N-=(14.01*g*mol^-1)/(144.94*g*mol^-1)xx100%=9.67%

And %H-=(4xx1.00794*g*mol^-1)/(144.94*g*mol^-1)xx100%=2.80%

This is always the problem when you use iodides...their salts are so heavy that you have to add a large mass to get the required equivalence. Iodides have some good solubilities in solvents such as acetone...