What is the perimeter of a rectangle that is #7 1/2 # yd by #8 1/2 # yd?

Question

861 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-17T15:40:31

See a solution process below:

First, convert the two dimensions from mixed numbers to improper fractions:

#7 1/2 = 7 + 1/2 = (2/2 xx 7) + 1/2 = 14/2 + 1/2 = (14 + 1)/2 = 15/2#

#8 1/2 = 8 + 1/2 = (2/2 xx 8) + 1/2 = 16/2 + 1/2 = (16 + 1)/2 = 17/2#

The formula for the perimeter of a rectangle is:

#p = 2l + 2w# or #p = 2(w + l)#

Substituting for #w# and #l# and calculating #p# gives:

#p = 2(15/2 + 17/2)#

#p = 2 xx (15 + 17)/2#

#p = 2 xx 32/2#

#p = 2 xx 16#

#p = 32#

Answer 2 · 2017-10-18T13:49:23

#32yd#

the perimeter can be calculated by

#P=2xx#(length +width)#

#p=2(7 1/2+ 8 1/2)#

we have straightforward fractions to add

#P=2xx16=32#