What is the perimeter of a rhombus whose diagonals are 16 and 30?

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Answer 1 · 2017-04-19T03:13:05

The perimeter is #68#.

The formula for perimeter of a rhombus where only the diagonals are known is:

#P=2sqrt(a^2+b^2)#, where #P=#Perimeter, and #a# and #b# are the diagonals.

With the given data:

#P=2sqrt(16^2+30^2)#

#P=2sqrt(256+900)#

#P=2sqrt1156#

Factorise to find the square root.

#P=2sqrt(2*2*17*17)#

#P=2sqrt(34*34)#

#P=2xx34#

#P=68#