What is the perimeter of a triangle with corners at #(1 ,2 )#, #(8 ,3 )#, and #(4 ,1 )#?

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Answer 1 · 2016-11-17T18:51:02

#Perimeter ~~ 14.7#

Given: #A = (1, 2), B = (8,3) and C = (4,1)#

The length of AB is:

#AB = sqrt((8 - 1)^2 + (3 - 2)^2) = sqrt(50) = 5sqrt(2)#

The length of BC is:

#BC = sqrt((4 - 8)^2 + (1 - 3)^2) = sqrt(20) = 2sqrt(5)#

The length of CA is:

#CA = sqrt((1 - 4)^2 + (2 - 1)^2) = sqrt(10)#

#Perimeter = AB + BC + CA#

#Perimeter = 5sqrt(2) + 2sqrt(5) + sqrt(10)#

#Perimeter ~~ 14.7#