Question

What is the perimeter of a triangle with corners at `(1 ,2 )`, `(8 ,3 )`, and `(4 ,4 )`?

Answer 1

Perimeter of triangle `= 14.8` units

Explanation:

Side A = `sqrt((8-1)^2+(3-2)^2) =sqrt 50 = 7.07`
Side B = `sqrt((4-8)^2+(4-3)^2) =sqrt 17 = 4.12`
Side C = `sqrt((1-4)^2+(2-4)^2) =sqrt 13 = 3.61`
Perimeter of triangle`= 7.07+4.12+3.61 = 14.8` units [Ans]