# What is the perimeter of a triangle with corners at (1 ,5 ), (6 ,3 ), and (4 ,1 )?

May 15, 2018

$13.21$ to 2 decimal points. (in surd form: $\sqrt{29} + 5 + 2 \sqrt{2}$ )

#### Explanation:

There are many ways to approach this.

Let
A = $\left(1 , 5\right)$
B = $\left(6 , 3\right)$
C = $\left(4 , 1\right)$

Use the formula:

$d = \setminus \sqrt{{\left({x}_{1} - {x}_{2}\right)}^{2} + {\left({y}_{1} - {y}_{2}\right)}^{2}}$

to work out the distance between individual points.

Use this to work out AB, AC, and BC.