# What is the perimeter of a triangle with corners at (1 ,9 ), (5 , 2 ), and (9 ,4 )?

Nov 20, 2016

$\sqrt{65} + \sqrt{89} + \sqrt{20}$ =21.9683

#### Explanation:

Distance between (1,9) and (5,2) would be = $\sqrt{{\left(5 - 1\right)}^{2} + {\left(2 - 9\right)}^{2}} = \sqrt{65}$

Distance between (1,9) and (9,4) would be =$\sqrt{{\left(9 - 1\right)}^{2} + {\left(4 - 9\right)}^{2}} = \sqrt{89}$

Distance between (5,2) and (9,4) would be= sqrt ((9-5)^2 +(4-2)^2))= sqrt 20

Perimeter would be $\sqrt{65} + \sqrt{89} + \sqrt{20}$ =21.9683