# What is the perimeter of a triangle with corners at (3 ,9 ), (5 ,2 ), and (1 ,4 )?

Perimeter of the triangle is $17.14 \left(2 \mathrm{dp}\right)$ Units
The Length of sides of the triangle are $A B = \sqrt{{\left(2 - 9\right)}^{2} + {\left(5 - 3\right)}^{2}} = \sqrt{53} = 7.28$ $B C = \sqrt{{\left(4 - 2\right)}^{2} + {\left(1 - 5\right)}^{2}} = \sqrt{20} = 4.47$ $C A = \sqrt{{\left(9 - 4\right)}^{2} + {\left(3 - 1\right)}^{2}} = \sqrt{29} = 5.39$Hence Perimeter of the triangle is $A B + B C + C A = 7.28 + 4.47 + 5.39 = 17.14 \left(2 \mathrm{dp}\right)$units [Ans]