Question

What is the perimeter of a triangle with corners at `(3 ,9 )`, `(5 ,2 )`, and `(1 ,4 )`?

Answer 1

Perimeter of the triangle is `17.14 (2dp)` Units

Explanation:

The Length of sides of the triangle are `AB=sqrt((2-9)^2+(5-3)^2)=sqrt53=7.28` `BC=sqrt((4-2)^2+(1-5)^2)=sqrt20=4.47` `CA=sqrt((9-4)^2+(3-1)^2)=sqrt29=5.39`Hence Perimeter of the triangle is `AB+BC+CA=7.28+4.47+5.39=17.14 (2dp)`units [Ans]