What is the perimeter of a triangle with corners at #(3 ,9 )#, #(5 ,7 )#, and #(1 ,4 )#?

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Answer 1 · 2018-04-14T11:42:38

Perimeter of the triangle is # 13.22# unit

#A(3,9),B(5,7),C(1,4) # are the three vertices of triangle.

Distance between two points #(x_1,y_1) and (x_2,y_2)# is

#D= sqrt((x_1-x_2)^2+(y_1-y_2)^2)#

#AB^2=(3-5)^2+(9-7)^2 =8 :. AB= sqrt 8~~2.83 # unit

#BC^2=(5-1)^2+(7-4)^2 =25 :. BC= 5 # unit

#CA^2=(1-3)^2+(4-9)^2 =29 :. CA= sqrt 29~~5.39 # unit

Perimeter of the triangle is #P=AB+BC+CA# or

#P=2.83+5.0+5.39 ~~13.22# unit [Ans]