What is the perimeter of a triangle with corners at #(6 ,0 )#, #(5 ,2 )#, and #(5 ,4 )#?

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Answer 1 · 2018-02-01T06:15:00

Perimeter of the triangle #P = color(brown)(8. 5953)#

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Given : #A (6,0) , B (5,2), C (5,4)#

Distance between two points, given the two end points' coordinates is given by the formula,

#d = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)#

#a = sqrt((5-6)^2 + (2-0)^2) = sqrt(1^2 + 2^2) ~~ color(green)(2.2361)#

#b = sqrt((6-5)^2 + (0-4)^2) = sqrt(1^2 + 4^2) ~~ color(green)(4.1231)#

#c = sqrt((6-5)^2 + (0-2)^2) = sqrt(1^2 + 2^2) = color(green)(2.2361)#

It is an isosceles triangle with sides a & c = 2.2361.

Perimeter of the triangle #P = (a + b + c) / 2 = ( 2.2361 + 4.1231 + 2.2361) / 2 = color(brown)(8. 5953)#