What is the perimeter of a triangle with corners at (6 ,5 ), (9 ,1 ), and (3 ,4 )?

1 Answer
Jul 3, 2016

It is 12.4.

Explanation:

We need to find the distances between the points.
We start assigning a letter to each point

A=(6,5), B=(9,1), C=(3,4)

The distances are

AB=sqrt((6-9)^2+(5-1)^2)=sqrt(9+16)=5

AC=sqrt((6-3)^2+(5-4)^2)=sqrt(9+1)\approx3.16

BC=sqrt((9-3)^2+(1-4)^2)=sqrt(9+9)\approx4.24.

The perimeter is then

AB+AC+BC=5+3.16+4.24=12.4.